If you come from the programming world of C/C++ or java or any other traditional programming languages you might fall into the trap of using for loops for the calculation of functions. This works as expected but it is much slower than what matlab can do. The following example demonstrates this principle (which you should not use if you can)

```Data2D = zeros([xPoints yPoints]); for xi = 1:xPoints x = xAxis(xi); for yi = 1:yPoints y = yAxis(yi); Data2D(xi,yi) = Ripple(x, y); end end```

On my computer it takes 10.3 seconds for 1.000.000 datapoints.

If the function depends on a single variable one should use a vector and for two variables one should use matrices instead. The following example demonstrates how to calculate a functions with two variables in a single step:

```xMat = (xAxis' * ones([1 yPoints]))'; yMat = yAxis' * ones([1 xPoints]); Data2D = Ripple(xMat, yMat);```

On my computer it takes 0.12 seconds for 1.000.000 datapoints, which is approx 90 times faster.

This is the complete code that was used

```% clear command window, figures and all variables clc; clf; clear all;   %% Definition of calculation constants   % calculation of axis xMax = 15; xPoints = 1000; xAxis = linspace(-xMax, xMax, xPoints);   yMax = 12; yPoints = 1000; yAxis = linspace(-yMax, yMax, yPoints);   %% function, here inline since it is rather simple Ripple = @(x,y) ( (cos(sqrt(x.*x+y.*y) + cos(sqrt(((x+.913*2*pi).*(x+.913*2*pi))+y.*y)) + cos(sqrt(((x-.913*2*pi).*(x-.913*2*pi))+(y.*y))))*4) );   %% Calculation % calculate in single line (fastest method) xMat = (xAxis' * ones([1 yPoints]))'; yMat = yAxis' * ones([1 xPoints]); tic; Data2D = Ripple(xMat, yMat); display(['calculated ' num2str(xPoints*yPoints) ' datapoints in ' num2str(toc) ' seconds']);   Data2D = Data2D / max(max(Data2D)); % normalize```